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Bearing Capacity and Critical Normal Stress Distribution of Soils by Method of Variational Calculus

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Abstract

A mathematical technique is hereby advanced for investigating the bearing capacity and associated normal stress distribution at failure of soil foundations. The stability equations are obtained using the limit equilibrium (LE) conditions.

The additions of vertical, horizontal and rotational equilibria are transformed mathematically with respect to the soil shearing strength, leading to the derivation of the equation of the functional Q, and two integral constraints.

Generally, no constitutive law beyond the conlomb’s yield criterion is incorporated in the formulation. Consequently, no constraints are placed on the character of the criticals except the overall equilibrium of the failing soil section.

The critical normal stress distribution, 6min, and consequently the load, Qmin, determined as a result of the minimization of the functional are the smallest stress and load parameters that can cause failure.

Introduction

Many of the problems encountered in soil Mechanics and Foundation Engineering Designs are the extreme-value type.

These problems include the stability of sloppy soil, the bearing capacity of foundations on horizontal, adjacent to sloppy soil and on sloppy soil, the limiting forces (active-Pa and passive Pp) acting on retaining structures like retaining walls, dams, sheet pile walls and others.

All problems of the types mentioned above can be solved within the framework of the limiting equilibrium (LE) approach. This approach which considers the overall stability of a “test body” bounded by soil surface [y(x)] and ship surface [y(x)] is based on the following three concepts [1].

Satisfaction of failure criteria S = f (6) along the ship surface, y(x) over which distribution. ý (x) and 6 (x) constitute the shear and normal stresses  Satisfaction of all equilibrium equations for the test body (vertical,  horizontal and rotational equilibria).

Extremization of the factor S with respect to two unknown functions y(x) and 6 (x). Thus S is considered to be function of these (y (x) and 6 (x) functions. The extreme value is defined as; Sex = Extr S [y (x) , 6 (x)

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